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Home  >>  EAMCET  >>  Mathematics
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$\large\frac{d}{dx}$$ \bigg[a \tan ^{-1} + b \log \bigg(\large\frac{x-1}{x+1}\bigg)\bigg]=\frac{1}{x^4-1}$$=>a-2b=$

\[\begin {array} {1 1} (1)\;1 & \quad (2)\;-1 \\ (3)\;0 & \quad (4)\;2 \end {array}\]

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(2) -1 is the correct answer.
answered Jan 20, 2014 by meena.p
 
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