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$\int \bigg(\large\frac{2 -\sin 2x}{1-\cos 2x}\bigg)$$e^x dx=$

\[\begin {array} {1 1} (1)\;-e^x \cot x +c & \quad (2)\;e^x \cot x +c \\ (3)\;2e^x \cot x +c & \quad (4)\;-2e^{x} \cot x +c \end {array}\]

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1 Answer

$ (1)\;-e^x \cot x +c$
answered Nov 7, 2013 by pady_1
 

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