Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

If earth were to rotate on its own axis such that the weight of a person at the equator becomes half the weight at the poles, then its time period of rotation is (g = acceleration due to gravity near the poles and R is the radius of earth) ( Ignore equatorial bulge)

$\begin {array} {1 1} (1)\;2 \pi \sqrt {\large\frac{2R}{g}} & \quad (2)\;2 \pi \sqrt{\large\frac{R}{2g}} \\ (3)\;2 \pi \sqrt{\large\frac{R}{3g}} & \quad (4)\;2 \pi \sqrt{ \large\frac{R}{g}} \end {array}$

Can you answer this question?

1 Answer

0 votes
(1) $ 2 \pi \sqrt{\large\frac{2R}{g}}$
answered Nov 7, 2013 by pady_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App