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# If $I_n=\int \sin ^n x dx$, then $n\; I_n-(n-1)I_{n-2}$=

$\begin {array} {1 1} (1)\;\sin ^{n-1} x \cos x & \quad (2)\;\cos ^{n-1} x \sin x \\ (3)\;-\sin ^{n-1}x \cos x & \quad (4)\;-\cos ^{n-1}x \sin x \end {array}$

Can you answer this question?

$(3)\;-\sin ^{n-1}x \cos x$
answered Nov 7, 2013 by