logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Physics

A body is projected vertically upwards at time $t=0$ and it is seen at a height $'H'$ at time $t_1$ and $t_2$ seconds during its flight. The maximum height attained is : (g is acceleration due to gravity)

\[\begin {array} {1 1} (1)\;\frac{g(t_2-t_1)^2}{8} & \quad (2)\;\frac{g(t_2-t_1)^2}{4} \\ (3)\;\frac{g(t_1+t_2)^2}{8} & \quad (4)\;\frac{g(t_2-t_1)^2}{4} \end {array}\]
Download clay6 mobile app

1 Answer

$(3)\;\frac{g(t_1+t_2)^2}{8}$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
Tag:MathPhyChemBioOther
...
X