Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

Two sources A and B are sending notes of frequency $680\;Hz.$ A listener moves from A to B with a constant velocity 'u'. If the speed of sound in air is $340 ms^{-1}$, What must be the value of $'u'$ so that he hears 10 beats per second?

\[\begin {array} {1 1} (1)\;2.0\;m-s^{-1} & \quad (2)\;2.5 m-s^{-1} \\ (3)\;3.0 m-s^{-1} & \quad (4)\;3.5 m-s^{-1} \end {array}\]
Can you answer this question?

1 Answer

0 votes
(2) $2.5 ms^{-1}$
answered Nov 7, 2013 by pady_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App