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# Suppose $\sin^2x\sin 3x=\sum\limits_{m=0}^{n}C_m\cos mx$ is an identity in $x$ where $C_0,C_1.......C_n$ are constants and $C_n\neq 0$ then the value of n is

$(a)\;6\qquad(b)\;5\qquad(c)\;4\qquad(d)\;3$

$\sin^3x.\sin 3x=\sum\limits_{m=0}^{n}C_m\cos mx$
$\sin^3x\sin 3x=\large\frac{1}{4}$$[3\sin x-\sin 3x]\sin 3x \qquad\qquad\;\;\;=\large\frac{1}{4}$$[\large\frac{3}{2}$$.2\sin x.\sin 3x-\sin^23x] \qquad\qquad\;\;\;=\large\frac{1}{4}$$\big[\large\frac{3}{2}$$(\cos 2x-\cos x)-\large\frac{1}{2}$$(1-\cos x)\big]$