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In Young's double slit experiment, the 10th maximum. When the wavelength $\lambda _1$ is at a distance of $y_1$ from the central maximum. When the wavelength of the source is changed to $\lambda_2,5$ th maximum is at a distance of $y_2$ from its central maximum. The ratio $\bigg(\large\frac{y_1}{y_2}\bigg)$is :

\[\begin {array} {1 1} (1)\;\frac{2 \lambda_1}{\lambda_2} & \quad (2)\;\frac{2 \lambda_2}{\lambda_1} \\ (3)\;\frac{ \lambda_1}{2\lambda_2} & \quad (4)\;\frac{\lambda_2}{2\lambda_1}\end {array}\]

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$(1)\;\frac{2 \lambda_1}{\lambda_2}$
answered Nov 7, 2013 by pady_1

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