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A bar magnet of 10 cm long is kept with its north (N)-pole pointing North. A neutral point is formed at a distance of 15 cm from each pole. Given the horizontal component of earth's field is $0.4$ Gauss, the pole strength of the magnet is :

\[\begin {array} {1 1} (1)\;9\;amp-m & \quad (2)\;6.75\;amp-m \\ (3)\;27\; amp-m & \quad (4)\;13.5\;amp-m \end {array}\]
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answered Nov 7, 2013 by pady_1

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