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Questions  >>  JEEMAIN and NEET  >>  NEET PAST PAPERS  >>  2019
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The displacement of a particle executing simple harmonic motion is given by $y = A0 + Asin{\omega}{t}+ Bcos\omega{t}$. Then the amplitude of its oscillation is given by :


( A ) $A+B$
( B ) $\sqrt{{A^2}+{B^2}}$
( C ) $\sqrt{A_\omicron^{2}{A^2}+{B^2}}$
( D ) $A_\omicron\sqrt{{A^2}+{B^2}}$

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