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The $ K_{ \alpha} - $ X-ray of molybdenum has a wave length of $ 71 \times 10^{-12}m$. If the energy of a molybdenum atom with K-electron removed is 23.32 KeV, then the energy of molybdenum atom when an L-electron removed is $(hc = 12.42 \times 10^{-7} eV)$

$\begin {array} {1 1} (1)\;17.5\: KeV & \quad (2)\;40.82\: KeV \\ (3)\;23.32 KeV & \quad (4)\;5.82\: KeV \end {array}$

1 Answer

(4) 5.82 KeV
answered Nov 7, 2013 by pady_1
 

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