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The emf of a cell E is 15 V as shown in the figure with an internal resistance of $ 0.5 \Omega $. Then the value of the current drawn from the cell is

$\begin {array} {1 1} (1)\;3\: A & \quad (2)\;2\: A \\ (3)\;5\: A & \quad (4)\;1\: A \end {array}$

1 Answer

(4) 1 A
answered Nov 7, 2013 by pady_1
 

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