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Q)

cos510 cos330 +sin390 cos120 =-1

cos510 cos330 +sin390 cos120 =-1

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A)
cos(180+x)=cos(x). cos(180-x)= -cos(x). sin(180+x)= -sin(x). sin(180-x)=sin(x). cos(510)cos(330)+sin(390)cos(120) = cos(3*180-30)cos(2*180-30)+sin(2*180+30)+cos(90+30) = -cos(30)*cos(30) + sin(30)* -sin(30) = -1
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