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A photon of energy 'E' ejects a photo electron from a metal surface whose work function is $W_0$. If this electron enters into a uniform magnetic field of induction 'B' in a direction perpendicular to the field and describes a circular path of radius 'R' , then the radius 'r' is given by , (in the usual notation):

\[\begin {array} {1 1} (1)\;\sqrt {\frac{2m(E-W_0)}{eB}} & \quad (2)\;\sqrt {2m(E-W_0)eB} \\ (3)\;\frac{\sqrt {2e(E-W_0)}}{mB} & \quad (4)\;\frac{\sqrt {2m(E-W_0)}}{eB} \end {array}\]

2 Answers

$ (4)\;\frac{\sqrt {2m(E-W_0)}}{eB} $
answered Nov 7, 2013 by pady_1
Explanation please
Explanation please
answered Apr 28 by vijay0123.vs

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