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Given that $\Delta H_f(H)=218 kJ/mol,$ express the $H-H$ bond energy in Kcal/mol:

\[\begin {array} {1 1} (1)\;52.15 & \quad (2)\;911 \\ (3)\;104 & \quad (4)\;52153 \end {array}\]

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1 Answer

(3) 104
answered Nov 7, 2013 by pady_1
i think it should be 52.13
as we know
1kj=0.2319kcal
 

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