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Fluorine reacts with dilute $NaOH$ and forms a gaseous and forms a gaseous product $\underline{A}$. The bond angle in the molecule of $\underline{A}$ is :

\[\begin {array} {1 1} (1)\;104^{\circ}40' & \quad (2)\;103^{\circ} \\ (3)\;107^{\circ} & \quad (4)\;109^{\circ}28' \end {array}\]
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answered Nov 7, 2013 by pady_1

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