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If the solubility product of $MgF_2$ at a certain temperature is $ 1.08 \times 10^{-10}$ , its solubility in mol $1^{-1}$ is:

$\begin {array} {1 1} (1)\;1.04 \times 10^{-5} & \quad (2)\;7.3 \times 10^{-4} \\ (3)\;3.0 \times 10^{-5} & \quad (4)\;3.0 \times 10^{-4} \end {array}$

1 Answer

(4) $3.0 \times 10^{-4}$
answered Nov 7, 2013 by pady_1
 

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