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Zinc reacts with hot and concentrated NaOH and forms :

$\begin {array} {1 1} (1)\;H_2 & \quad (2)\;Zn(OH)_2+Na_2O \\ (3)\;ZnO & \quad (4)\;O_2 \end {array}$

1 Answer

(1) $H_2$
answered Nov 7, 2013 by pady_1
 
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