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Q)

Calculate no.of atoms present in 3.2g of sulphur

Calculate no.of atoms present in 3.2g of sulphur

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A)
32g of sulphur contains = $6.023 \times 10^{23} atoms$

So 3.2 g of sulphur contain = $\large\frac{6.023\times 10^{23}\times 3.2}{32}$

No of atoms = $6.023\times 10^{22}$
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