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Q)

A partical is projected from ground at some angle with the horizontal.let p

A partical is projected from ground at some angle with the horizontal.let p be the point at maximum height h. At what height above the point p should the partical be aimed to have range equal to maximum height

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A)

he range of a projectile launched at velocity Vo and an angle θ to the horizontal is:

R = (Vo^2 Sin2θ)/g

The maximum height of a projectile is:

H = (Vo Sinθ)^2 / 2g

So, setting R = H gives

(Vo^2 Sin2θ)/g = (Vo Sinθ)^2/2g or

2Vo^2 Sin2θ = Vo^2 Sinθ^2 or

2Sin2θ = Sinθ^2

 θ = 1.3258 rad or 75.963°

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