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Consider the following statements for the reaction

$KIO_3+5KI+6HCI \rightarrow 3I_2 +6KCI+3H_2O$

(1) $I $ is reduced to $I_2$

(2) $IO_3$ is oxidized to $I_2$

(3)  $IO_3$ is reduced to $I_2$

(4) Oxidation number of $I$ increases from $ -I \: ( in\: KI)$ to zero $ ( in\: I_2)$

The correct statement are

$\begin {array} {1 1} (1)\;1,2 \: and \: 4 & \quad (2)\;3\: and \: 4 \\ (3)\;1\: and \: 4 & \quad (4)\;1,3\: and \: 4 \end {array}$

1 Answer

(2) 3 and 4
answered Nov 7, 2013 by pady_1
 
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