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# The percentage error in measuring radius of a sphere is found to be $0.05\%$ calculate the percentage of error is measuring its volume

$\begin{array}{1 1} (a) \;0.015\% \\ (b) \;0.15\% \\ (c) \;0.005\% \\ (d) \;0.25\% \end{array}$

$V= 4 \pi r^3$
$\large\frac{\Delta V}{V}=3 \frac{\Delta r}{r}$$= 3 \times 0.05\%$
$\qquad= 0.15\%$