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# If Area(A) , velocity(V) and density $(\rho)$ are base units , then dimensional formula of force

$\begin{array}{1 1} (a) \;AV \rho \\ (b) \;AV^2 \rho \\ (c) \;AV \rho^2 \\ (d) \;A^2V \rho \end{array}$

Let $F= A^xV^y\rho^z$
$MLT^{-2}=[L^2]*(LT^{-1}]^y[ML^{-3}]^z$
$1=z$
$1=2x+y-3z$
$-2=-y$
$y=2$
$x=1$
$\therefore F= AV^2\rho$