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Q)

A box contains 7red and 4 blue balls Two balls are drawn at random with re

A box contains 7red and 4 blue balls Two balls are drawn at random with replacement.find the probability that 1)2 red balls 2) two blue balls 3) one ball is red and one is blue

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A)
The urn contains 7 red and 4 blue balls.

Total number of balls in the bag = 7 + 4 = 11

Two balls are drawn at random from the bag with replacement.

We know that:

Probability of an event E =number of outcomes favourable to event E/total outcome

P(Getting one red ball)=7C1/11C1=7/11

P(Getting one blue ball) =4C1/11C1=4/11

P(Getting 2 red balls) =7/11 *7/11=49/121

P(Getting 2 blue balls) =4/11*4/11=16/121

P(Getting one red and one blue ball)=7/11*4/11=28/121
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