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$20\; ml$ of $0.1\;M$ acetic acid is mixed with $50\;ml$ of Potassium acetate. $K_a$ of Acetic acid = $1.8 \times 10^{-5}$ at $27^{\circ}C$. The concentration of Potassium acetate if pH of the mixture is $4.8$:

\[\begin {array} {1 1} (1)\;0.1\;M & \quad (2)\;0.04\;M \\ (3)\;0.4\;M & \quad (4)\;0.02\;M \end {array}\]

1 Answer

(2) 0.04 M
answered Nov 7, 2013 by pady_1
 

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