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If $f:[-6,6] \to \Re$ is defined by $f(x)=x^2-3$ for $x \in \Re$, then $(f0f0f)(-l)+(f0f0f)(0)+(f0f0f)(l)=$

\[\begin {array} {1 1} (1)\;f(4 \sqrt 2) & \quad (2)\;f(3 \sqrt 2) \\ (3)\;f(2 \sqrt 2) & \quad (4)\;f(\sqrt {2}) \end {array}\]

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$ (1)\;f(4 \sqrt 2)$
answered Nov 7, 2013 by pady_1
 

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