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Home  >>  EAMCET  >>  Mathematics
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Given that $a,b \in \{0,1,2,.........,9\}$ with $ a+b \neq 0$ and that $\bigg(a, \large\frac{b}{10}$$ \bigg)^x=\bigg(\large\frac{a}{10},\frac{b}{100}\bigg)^y$$-1000$ Then $\large\frac{1}{x}-\frac{1}{y}=$

\[\begin {array} {1 1} (1)\;1 & \quad (2)\;\frac{1}{2} \\ (3)\;\frac{1}{3} & \quad (4)\;\frac{1}{4} \end {array}\]

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1 Answer

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(3) $\frac{1}{3}$
answered Nov 7, 2013 by pady_1
 

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