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The cubic equation whose roots are thrice to each of the roots of $x^3+2x^2-4x+1=0$ is

\[\begin {array} {1 1} (1)\;x^3-6x^2+36 x+27=0 & \quad (2)\;x^3+6x^2+36 x+27=0 \\ (3)\;x^3-6x^2-36 x+27=0 & \quad (4)\;x^3+6x^2-36 x+27=0 \end {array}\]

1 Answer

$(4) x^3+6x^2-36 x +27=0$ is the correct answer.
answered Jan 20, 2014 by meena.p
 
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