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Questions  >>  CBSE XI  >>  Physics
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A body starts from rest. What is the ratio of the distance travelled by the body during fourth and 2nd second

$\begin{array}{1 1} (a) \;\frac{1}{7} \\ (b) \;\frac{5}{7}\\ (c) \;\frac{3}{7} \\ (d) \;\frac{7}{3}\end{array} $

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A)
Solution :
$S_n= u+\large\frac{a}{2}$$(2n-1)5u=0$
$s_4=\large\frac{a}{2}$$((2 \times 4)-1)=\large\frac{73}{2}$
$s_2=\large\frac{a}{2}$$((2 \times 2)-1)=\large\frac{39}{2}$
$\large\frac{s_4}{s_2}=\frac{7}{3}$
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