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Questions  >>  CBSE XI  >>  Physics
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Q)

The velocity of bullet is reduced from 200 m/s to 100 m/s. While travelling through a wooden block, of thickness 10m.what is the retordation.

$\begin{array}{1 1} (a) \;10 \times 10^4\;m/s^2 \\ (b) \;12 \times 10^4\;m/s^2\\ (c) \;13.5 \times 10^4\;m/s^2 \\ (d) \;15 \times 10^4\;m/s^2\end{array} $

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A)
Solution :
$V^2-u^2=29S$
$100^2-200^2=2 \times a \times 10 \times 10^{-2}$
$-30000=2 \times a \times 10^{-1}$
$a= 15 \times 10^{4}\;m/s^2$
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