logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Mathematics
0 votes

If $\alpha +\beta+\gamma= 2\theta$, then $cos \theta+ \cos (\theta- \alpha)+ \cos (\theta- \beta)+ \cos (\theta- \gamma)=$

\[\begin {array} {1 1} (1)\;4 \sin \frac{\alpha}{2}. \cos \frac{\beta}{2}. \sin \frac{\gamma}{2} & \quad (2)\;4 \cos \frac{\alpha}{2}. \cos \frac{\beta}{2}. \cos \frac{\gamma}{2} \\ (3)\;4 \sin \frac{\alpha}{2}. \sin \frac{\beta}{2}. \sin \frac{\gamma}{2} & \quad (4)\;4 \sin \alpha.\sin \beta . \sin \gamma \end {array}\]
Can you answer this question?
 
 

1 Answer

0 votes
$(2)\;4 \cos \frac{\alpha}{2}. \cos \frac{\beta}{2}. \cos \frac{\gamma}{2}$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...