$\large\frac{1+ \tan h \Large\frac{x}{2}}{1- \tan h \Large\frac{x}{2}}=$

Question

\[\begin {array} {1 1} (1)\;e^{-x} & \quad (2)\;e^{x} \\ (3)\;2e^{x/2} & \quad (4)\;2e^{-x/2}\end {array}\]