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$\large\frac{1+ \tan h \Large\frac{x}{2}}{1- \tan h \Large\frac{x}{2}}=$

\[\begin {array} {1 1} (1)\;e^{-x} & \quad (2)\;e^{x} \\ (3)\;2e^{x/2} & \quad (4)\;2e^{-x/2}\end {array}\]

1 Answer

$(2)\;e^{-x}$
answered Nov 7, 2013 by pady_1
 
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