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find dy/dx if x = (t^2 -1 / t^2 + 1)^1/2 and y = at (t^2 - 1 /t^2 + 1)^1/2

find dy/dx if x = (t^2 -1 / t^2 + 1)^1/2 and y = at (t^2 - 1 /t^2 + 1)^1/2 by parametric form

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