logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Mathematics
0 votes

From the top of a hill the angles of depression of the top and the bottom of a pillar are $\alpha$ and $\beta$ respectively. The height (in meters) of the pillar is

\[\begin {array} {1 1} (1)\;\frac{h(\tan \beta- \tan \alpha)}{\tan \beta} & \quad (2)\;\frac{h(\tan \alpha- \tan \beta)}{\tan \alpha} \\ (3)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \beta} & \quad (4)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \alpha} \end {array}\]

Can you answer this question?
 
 

1 Answer

0 votes
$ (1)\;\frac{h(\tan \beta- \tan \alpha)}{\tan \beta}$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...