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From the top of a hill the angles of depression of the top and the bottom of a pillar are $\alpha$ and $\beta$ respectively. The height (in meters) of the pillar is

\[\begin {array} {1 1} (1)\;\frac{h(\tan \beta- \tan \alpha)}{\tan \beta} & \quad (2)\;\frac{h(\tan \alpha- \tan \beta)}{\tan \alpha} \\ (3)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \beta} & \quad (4)\;\frac{h(\tan \beta + \tan \alpha)}{\tan \alpha} \end {array}\]

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$ (1)\;\frac{h(\tan \beta- \tan \alpha)}{\tan \beta}$
answered Nov 7, 2013 by pady_1

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