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JEEMAIN and NEET
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Trigonometry
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If $u=\sqrt{a^2\cos^2\theta+b^2\sin^2\theta}+\sqrt{a^2\sin^2\theta+b^2\cos^2\theta}$ then the difference between the maximum and minimum values of $u^2$ is given by
$\begin{array}{1 1}(a)\;(a-b)^2&(b)\;2\sqrt{a^2+b^2}\\(c)(a+b)^2&(d)\;2(a^2+b^2)\end{array}$
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