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If the lines $2x-3y=5$ and $3x-4y=7$ are two diameters of a circle of radius 7, then the equation of the circle is
\[\begin {array} {1 1} (1)\;x^2+y^2+2x-4y-47=0 & \quad (2)\;x^2+y^2=49 \\ (3)\;x^2+y^2-2x+2y-47=0 & \quad (4)\;x^2+y^2=17 \end {array}\]
jeemain
eamcet
math
2008
q53
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Oct 17, 2013
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meena.p
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$ (3)\;x^2+y^2-2x+2y-47=0$
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Nov 7, 2013
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pady_1
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