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EAMCET
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Mathematics
For an ellipse with eccentricity $\large\frac{1}{2}$ the center is at the orgin. If one directrix is $x=4$, then the equation of the ellipse is
\[\begin {array} {1 1} (1)\;3x^2+4y^2=1 & \quad (2)\;3x^2+4y^2=12 \\ (3)\;4x^2+3y^2=1 & \quad (4)\;4x^2+3y^2=12 \end {array}\]
jeemain
eamcet
math
2008
q57
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Oct 17, 2013
by
meena.p
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1 Answer
$ (2)\;3x^2+4y^2=12$
answered
Nov 7, 2013
by
pady_1
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