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# The radius of the circle with the polar equation $r^2-8r (\sqrt 3 \cos \theta+\sin \theta)+15 -0$ is

$\begin {array} {1 1} (1)\;8 & \quad (2)\;7 \\ (3)\;6 & \quad (4)\;5 \end {array}$

(2) 7

+1 vote