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Home  >>  EAMCET  >>  Mathematics
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The radius of the circle with the polar equation $r^2-8r (\sqrt 3 \cos \theta+\sin \theta)+15 -0$ is

\[\begin {array} {1 1} (1)\;8 & \quad (2)\;7 \\ (3)\;6 & \quad (4)\;5 \end {array}\]

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(2) 7
answered Nov 7, 2013 by pady_1
 
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