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If $f(2)=4$ and $f'(2)=1$, then $\lim \limits_{x \to 2} \large\frac{x f(2) -2 f(x)}{x-2}=$

\[\begin {array} {1 1} (1)\;-2 & \quad (2)\;1 \\ (3)\;2 & \quad (4)\;3 \end {array}\]

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