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$\int \limits _0^1 x^{3/2} \sqrt {1-x}dx=$

\[\begin {array} {1 1} (1)\;\frac{\pi}{6} & \quad (2)\;\frac{\pi}{9} \\ (3)\;\frac{\pi}{12} & \quad (4)\;\frac{\pi}{16} \end {array}\]

1 Answer

$(4)\;\frac{\pi}{16}$
answered Nov 7, 2013 by pady_1
 
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