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$\int \limits_{-\pi/2}^{\pi/2} \sin |x| dx=$

\[\begin {array} {1 1} (1)\;0 & \quad (2)\;1 \\ (3)\;2 & \quad (4)\;\pi \end {array}\]

1 Answer

(3) 2
answered Nov 7, 2013 by pady_1
 
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