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The solution of the different equation $\large\frac{dy}{dx}=\frac{xy+y}{xy+x}$ is

\[\begin {array} {1 1} (1)\;x+y= \log \bigg(\frac{Cy}{x} \bigg) \\ (2)\;x+y-log (Cxy) \\ (3)\;x-y= \log \bigg(\frac{Cx}{y}\bigg)\\ (4)\;y-x-\log \bigg(\frac{Cx}{y}\bigg) \end {array}\]

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1 Answer

$(4)\;y-x-\log \bigg(\frac{Cx}{y}\bigg)$
answered Nov 7, 2013 by pady_1
 
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