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The moment of inertia of a thin circular disc about an axis passing through its centre and perpendicular to its diameter and touching the edge of the rim is

\[\begin {array} {1 1} (1)\;I & \quad (2)\;2I \\ (3)\;\frac{3}{2}I & \quad (4)\;\frac{5}{2}I \end {array}\]
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(4) $\frac{5}{2} I$
answered Nov 7, 2013 by pady_1

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