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Q)

If Vase I contain 02 white and 4 Black balls and Vase II contain 04 White a

If Vase I contain 02 white and 4 Black balls and Vase II contain 04 White and 4 black balls if a ball is drawn out of random from one of the two vase what is probability that it was a white ball

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A)
the probability of first one will be

 

no.of white balls / total no. of balls

 

i.e. 2/6=1/3

 

the probability of second one will be:

 

no. of white balls / total no. of balls

 

i.e. 4/8

 

=1/2

 

total probability :

 

no.of white balls / total no. of balls

 

i.e. 6/14

 

=3/7
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