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Home  >>  EAMCET  >>  Physics
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When a sound wave of wavelength $'\lambda'$ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is

\[\begin {array} {1 1} (1)\;\lambda & \quad (2)\;\frac{\lambda}{2} \\ (3)\;\frac{\lambda}{2 \pi} & \quad (4)\;\frac{\lambda}{4 \pi} \end {array}\]
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$ (3)\;\frac{\lambda}{2 \pi}$
answered Nov 7, 2013 by pady_1
 

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