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A current of 16 A is made to pass through a conductor in which the number density of free electrons is $ 4 \times 10^{28}m^{-3}$ and its area of cross section is $ 10^{-5}m^2$. The average drift velocity of free electrons in the conductor is

$\begin {array} {1 1} (1)\;2.5 \times \: 10^{-4}m.s^{-1} & \quad (2)\;3.2 \times \: 10^{-4}m.s^{-1} \\ (3)\;6.4 \times \: 10^{-4}m.s^{-1} & \quad (4)\;1.6 \times \: 10^{-4}m.s^{-1} \end {array}$

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(1) $2.5 \times \: 10^{-4}m.s^{-1}$
answered Nov 7, 2013 by pady_1
 

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