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A capillary tube of radius 'r' is immersed in water and water rises in it to a height 'h'. Mass of water in the capillary tube is $ 5 \times 10^{-3}kg$ . Another capillary tube of radius $ \bigg( \large\frac{r}{2} \bigg)$ is immersed in water. The mass of water that will rise in this tube is

$\begin {array} {1 1} (1)\;7.5 \times 10^{-3}kg & \quad (2)\;1 \times 10^{-3}kg \\ (3)\;2.5 \times 10^{-3}kg & \quad (4)\;5 \times 10^{-3}kg \end {array}$

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(3) $ 2.5 \times 10^{-3}kg$
answered Nov 7, 2013 by pady_1

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