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An organic $C_3H_7Br(A)$ with alcoholic KOH forms $C_3H_6$ which decolorises $Br_2$ in $CCl_4$ but does not gives white precipitate with ammonical $AgNO_3(A) $ on reaction with $Na/C_2H_5OH$ produces n- butyl amine. Hence the compound (A) is

$\begin{array}{1 1} n-p-propyl\;bromide \\ isoprooyl\;bromide \\ l,l-dibromopropane \\ none\;of\;these \end{array} $

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