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When a battery connected across a resistor of $416 \Omega$, the voltage across the resistor is 12 V. When the same battery is connected across a resistor of $10 \Omega$, Voltage across it is 11V. The internal resistance of the battery in Ohms is

\[\begin {array} {1 1} (1)\;\frac{10}{7} & \quad (2)\;\frac{20}{7} \\ (3)\;\frac{25}{7} & \quad (4)\;\frac{30}{7} \end {array}\]

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$(2) \frac{20}{7}$
answered Nov 7, 2013 by pady_1

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