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A certain particle has a half life of 60 seconds. The fractions of the particles that will decay at the end of 10 seconds is

$\begin {array} {1 1} (1)\;(1-2^{-\large\frac{1}{6}}) & \quad (2)\;(1-2^{\large\frac{1}{6}}) \\ (3)\;(2^6-1) & \quad (4)\;2^{\large\frac{1}{6}} \end {array}$

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1 Answer

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(1) $ (1-2^{-\large\frac{1}{6}})$
answered Nov 7, 2013 by pady_1
 

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